In snippet, where is $2 in this substitution?
Transformation: ${1/^(\w)|(?:_(\w))/(?1\u$1:)(?2 \u$2:)/g}
Original: ${1:text_in_snail_case}
Output:
Transformation: Text In Snail Case
Original: text_in_snail_case
Where is "$2"?
inoue
#1
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r-stein
#2
You can just count the matching groups ?: means the group does not have a number
-
$0:^(\w)|(?:_(\w)) -
$1:(\w)in^(\w), i.e. first word char after start -
$2:(\w)in(?:_(\w)), i.e. word char after an underscore
3 Likes
inoue
#4
/([^%]|%%)*(%.)?.*/
in the above expression,
$0:/([^%]|%%)*(%.)?.*/
$1:([^%]|%%)*
$2:(%.)?
$3:.*
am I right?
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r-stein
#6
/ is not part of the expression so it would be $0:([^%]|%%)*(%.)?.*
also the matching groups are creating with parens so $3 would not exists and I am not sure what would be the content of $1, because the * is outside of the paren.
In general I would write something like that with ((?:[^%]|%%)*), i.e. you use ?: to not create a matching group, but create the matching group around the whole expression you want to match.
2 Likes